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refactor: remove show-if in favour of conditionals
This prevents a problem where show-if can trigger an error if a value is checked to exist with it. Signed-off-by: Philip Molares <philip.molares@udo.edu>
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52 changed files with 239 additions and 352 deletions
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@ -1,11 +1,10 @@
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/*
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* SPDX-FileCopyrightText: 2022 The HedgeDoc developers (see AUTHORS file)
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* SPDX-FileCopyrightText: 2023 The HedgeDoc developers (see AUTHORS file)
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*
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* SPDX-License-Identifier: AGPL-3.0-only
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*/
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import { Logger } from '../../../../utils/logger'
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import { UiIcon } from '../../icons/ui-icon'
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import { ShowIf } from '../../show-if/show-if'
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import { CopyToClipboardButton } from '../copy-to-clipboard-button/copy-to-clipboard-button'
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import React, { useCallback, useMemo } from 'react'
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import { Button, FormControl, InputGroup } from 'react-bootstrap'
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@ -54,13 +53,13 @@ export const CopyableField: React.FC<CopyableFieldProps> = ({ content, shareOrig
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<InputGroup.Text>
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<CopyToClipboardButton variant={'outline-secondary'} content={content} />
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</InputGroup.Text>
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<ShowIf condition={sharingSupported}>
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{sharingSupported && (
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<InputGroup.Text>
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<Button variant='secondary' title={'Share'} onClick={doShareAction}>
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<UiIcon icon={IconShare} />
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</Button>
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</InputGroup.Text>
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</ShowIf>
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)}
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</InputGroup>
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)
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}
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